Correct Answer - a
Suppose that the charge `-q_(1)` moves around the charge `q_(2)` along a circular path of radius `r` with spedd `v`.
The necessary centripetal force is provided by the electronic force of attraction between the two charges i.e.,
`(1)/(4piepsilon_(0)).(q_(1)xxq_(2))/(r^(2))= (mv^(2))/(r)`
Or `v= (1/(4piepsilon_(0)).(q_(1)xxq_(2))/(mr))^(1//2)`
If `T` is period of revolution of the charge `-q_(1)` about `q_(2)` then
`T=(2pir)/(v)`
Subsituting for `v` we get `T = sqrt((16pi^(3)epsilon_(0)mr^(3))/(q_(1)q_(2)))`