Question

Two parallel plates separated by a disatnce of `5 mm` are kept at a potential difference of `5.0 V`. A particle of mass `10^(15) kg` and change `10^(-11) C` centre in it with a velocity `10^(7) m//s`. The acceleration of the particle will be
A. `10^(8) m//s^(2)`
B. `5 xx 10^(5) m//s^(2)`
C. `10^(5) m//s^(2)`
D. `2 xx 10^(3) m//s^(2)`

Answer 1

Correct Answer - A
`a = (qE)/(m) = (q)/(m) ((V)/(d)) = (10^(-11))/(10^(-15)) xx (50)/(5 xx 10^(-3)) = 10^(8) m//sec^(2)`