Question

Consider a parallel plate capacitor of `10 muF` (micro-farad) with air filled in the gap between the plates. Now one half of the space between the plates is filled with a dielectric of dielectric constant `4`, as shown in the figure. The capacity of the capacitor charges to

A. `24 muF`
B. `20 muF`
C. `40 muF`
D. `5 muF`

Answer 1

Correct Answer - A
`C_(1) = (epsilon_(0)((A)/(4)))/(d), C_(2) = (Kepsilon_(0)((A)/(2)))/(d), C_(3) = (epsilon_(0)((A)/(4)))/(d)`
`C_(eq) = C_(1) + C_(2) + C_(3) = ((K + 1)/(2)) (epsilon_(0)A)/(d)`
`= ((4 + 1)/(2)) xx 10 = 25 muF`