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Consider a variation of the previous problem. Suppose the circular loop lies in a vertical plane. The rod has a mass m. The rod and the loop have negligible resistance but the wire connecting O and C has a resistance R. The rod is made to rotate with a uniform angular velocity `(omega)` in the clockwise direction by applying a force at the midpoint of OA in a direction perpendicular to it.
Find the magnitude of this force when the rod makes an angle `(theta)` with the vertical.
A. `(B^(2)a^(3)omega)/(2R)-mg sin theta`
B. `(B^(2)a^(3)omega)/(2R)+mg sin theta`
C. `(B^(2)a^(3)omega)/(R)-mg sin theta`
D. None of these

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Best answer
Correct Answer - A
We know that `F=(B^(2)a^(2)omega)/(2R)=0Bl`
Component of mg along `F=mg sin theta`
Net force `=(B^(2)a^(2)omega)/(2R)-mg sin theta`.

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