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A `100mH` coil carries a current of `1` ampere. Energy stored in its magnetic field is
A. `0.5J`
B. `1J`
C. `0.05J`
D. `0.1J`

1 Answer

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Best answer
Correct Answer - C
Energy `=(1)/(2)LI^(2)=(1)/(2)xx100xx10^(-3)xx1^(2)=0.05J`

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