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The current in a coil of inductance `5H` decreases at the rate of `2A//a`. The induced e.m.f. is

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The current in a coil of inductance `5H` decreases at the rate of `2A//a`. The induced e.m.f. is
A. `2 V`
B. `5 V`
C. `10 V`
D. `-10 V`
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Correct Answer - C
`e=-L(di)/(dt)`,since current decrease so`(di)/(dt)`isnegative, hence `e=-5(-2)=+10V`
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