Question

The rms value of an ac of 50Hz is 10A. The time taken by an alternating current in reaching from zero to maximum value and the peak value will be
A. `2xx10^(-2)sec` and `14.14 amp`
B. `1xx10^(-2)sec` and `7.07 amp`
C. `5xx10^(-3)sec` and `7.07 amp`
D. `5xx10^(-3)sec` and `14.14 amp`

Answer 1

Correct Answer - D
Time taken by the current to reach the maximum value `t=T/4=1/(4V)=1/(4xx50)=5xx10^(-3)sec`
and `i_(0)=i_(r.m.s)sqrt(2)=10sqrt(2)=14.14 amp`