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Instantaneous values of current and e.m.f in an AC circuit are `I=I//sqrt(2)sin 314` tamp and `E=sqrt(2)sin(314t-pi//6)V` respectively. The phase difference between `E` and `I` will be
A. `-pi//6 rad`
B. `-pi//3 rad`
C. `pi//6 rad`
D. `pi//3 rad`

1 Answer

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Best answer
Correct Answer - A
Phase difference relative to the current
`varphi=(314t-(pi)/6)-(314t)=-(pi)/6`

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