Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
313 views
in Physics by (93.7k points)
closed by
When a telescope is adjusted for parallel light, the distance of the objective from the eye piece is found to be `80 cm`. The magnifying power of the telescope is 19 . The focal length of the lenses are
A. `61 cm, 19 cm`
B. `40 cm, 40 cm`
C. `76 cm, 4 cm`
D. `50cm, 30 cm`

1 Answer

0 votes
by (94.0k points)
selected by
 
Best answer
Correct Answer - C
`f_(o)+f_(e)=80` and `(f_(o))/(f_(e))=19impliesf_(o)=76` and `f_(e)=4cm`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...