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What will be the angular width of central maxima in Fraunhofer diffraction when light of wavelength `6000Å` is used and slit width is `12xx10^-5cm`?

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What will be the angular width of central maxima in Fraunhofer diffraction when light of wavelength `6000Å` is used and slit width is `12xx10^-5cm`?
A. (a) `2rad`
B. (b) `3rad`
C. (c) `1rad`
D. (d) `8rad`
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Correct Answer - C
Angular width `=(2lambda)/(d)=(2xx6000xx10^(-10))/(12xx10^-5xx10^-2)=1rad.`
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