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At the first minimum adjacent to the central maximum of a single-slit diffraction pattern the phase difference between the Huygens wavelet from the edge of the slit and the wavelet from the mid-point of the slit is
A. (a) `pi/8` radian
B. (b) `pi/4` radian
C. (c) `2pi` radian
D. (d) `pi` radian

1 Answer

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Best answer
Correct Answer - D
For first minima at P, `a sin theta=lambda`
So phase difference `Deltalambda_1=(Deltax_1)/(lambda)xx2pi=((a//2)sintheta)/(lambda)xx2pi`
image
`Deltaphi_1=(lambda)/(2lambda)xx2pi=piradian`

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