Question

The magnetic flux density applied in a cyclotron is `3*5T`. What will be the frequency of electric field that must be applied between the dees in order (a) to accelerate protons (b) `alpha`-particles? mass of proton `1*67xx10^(-27)kg`.

Answer 1

(a) `v=(Bq)/(2pim)=(3*5xx1*6xx10^(-19))/(2xx(22//7)xx1*67xx10^(-27))=5*35xx10^7Hz`.
(b) `V=(Bxx2e)/(2pixx4m)=(3*5xx2xx1*6xx10^-19)/(2xx(22/7)xx4xx1*67xx10^(-27))=2*675xx10^7Hz`.