Question

The ratio of longest wavelength and the shortest wavelength observed in the five spectral series of emission spectrum of hydrogen is
A. `(4)/(3)`
B. `(525)/(376)`
C. `25`
D. `(900)/(11)`

Answer 1

Correct Answer - D
Shortest wavelength comes from `n_(1) = oo` to `n_(2) = 1` and longest wavelength comes from `n_(1) = 6` to `n_(1) = 5` in the
given. Case. Hence `(1)/(lambda_(min)) = R ((1)/(1^(2)) - (1)/(oo^(2)))= R`
`(1)/(lambda_(max)) = R ((1)/(5^(2)) - (1)/(6^(2)))= R ((36 - 25)/(25 xx 36)) = (11)/(900)R`
`:. (lambda_(max))/(lambda_(min)) = (900)/(11)`