Question

If the binding energy per nucleon in `L i^7` and `He^4` nuclei are respectively `5.60 MeV` and `7.06 MeV`. Then energy of reaction `L i^7 + p rarr 2_2 He^4` is.
A. 19.6 MeV
B. `-2.4 MeV`
C. 8.4 MeV
D. 17.3 MeV

Answer 1

Correct Answer - D
(d) The binding energy of `._1He^4 = 4xx 7.06 = 28.14 MeV`
The binding energy of `._3^7 Li + ._1^1 H rarr ._2He^4 +._2 He^4 + Q`
`39.20 28.24 xx 2 (=56.48 MeV)`.