Question

Answer the following questions :
Fig shows an inductor L and a resistance R connected in parallel to battery through a switch. The resistance of R is the same as that of the coil that makes L. Two identical bulbs are put in each arm of the circuit. (i) Which of the bulb be equally bright after some time ?

Answer 1

(i) The bulb `B_(2)` in arm R lights up earlier because induced e.m.f. across L opposes growth of current in `B_(1)`
(ii) Yes, both the bulbs will be equally bright after some time. This is because once the current has reached its maximum value, self inductance plays no role. Resistance of L and R is same, and both the bulbs are identical and are connected to same source of potential difference.