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In the Boolean algebra `bar((bar(A).bar(B))). A` equal to

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In the Boolean algebra `bar((bar(A).bar(B))). A` equal to
A. `bar(A+B)`
B. `A`
C. `bar(A.B)`
D. `A+B`
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Correct Answer - B
`bar(bar(A)+bar(B)).A=(bar(bar(A))+bar(bar(B))).A=(A+B).A`
`=A.A+AB=A+AB=A(1+B)=A`
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