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An electric motor operating on a `50 V dc` supply draws a current of `12 A`. If the efficiency of the motor is `30 %`,estimate the resistance of the windings of the motor.

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Here, `V = 50` volt, `I = 12` ampere.,
`eta = 30%, R = ?`
Input electric power ` = VI = 50 xx 12 = 600` watt
As efficiency is 30%, therefore, power dissipated as heat is 70% of this power
`P = (70)/(100) (VI) = (70)/(100) xx 600 = 420 W`
As `P = I^(2) :. R = (P)/(I^(2)) = (420)/(12 xx 12) = 2.9 Omega`

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