Question

For `CE` transistor amlifier, the audio signal voltage across the collector resistance of `2 k Omega` is `4V`. If the currents amplification factor of the transistor is `100` and the base resistance is `1 k Omega`, then the input signal voltage is
A. `30 mV`
B. `15 mV`
C. `10 mV`
D. `20mV`

Answer 1

Correct Answer - D
`beta=100, V_(0)=4V, R_(i)=10^(3) Omega`,
`R_(0)=2xx10^(3) Omega, V_(i)=?`
`(V_(0))/(V_(i))=beta(R_(0))/(R_(i)) implies 4/(V_(i))=100xx(2xx10^(3))/(10^(3))`
`implies V_(i)=20 mV`