Question

How much electricity is required in coulomb for the oxidation of :
(a) `1` mol of `H_(2)O` to `O_(2)`,
(b) `1` mole of `FeO` to `Fe_(2)O_(3)` ?

Answer 1

Eq. of `H_(2)O = (i.t)/(96500)`
`1` mole `H_(2)O = 2eq`.
`[2H_(2)O rarr 4H^(+)+4e+O_(2) :. EH_(2)O = (M_(H_(2)O))/(2)]`
`2 = (i.t)/(96500)`
`i.t = 96500 xx 2C = 2F`
(b) Eq. pf `FeO = (i.t)/(96500)`
`2Fe^(2+) rarr Fe_(2)^(3+)+2e`
`:. E_(FeO) = M_(FeO)`
`:.` valence factor for `FeO = 1`
or `1 = (i.t)/(96500)`
`i.t = 96500 C = 1F`