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A current of `2.0` ampere is passed for `5.0` hour through a molten tin salt to deposit `22.2 g` tin. What is the oxidation state of tin in salt? Atomic `wt.` of `Sn = 118.69 g`.

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Eq. of tin `= (i.t)/(96500)`
`(22.2)/(E) = (2 xx 5 xx 60 xx 60)/(96500)`
`E_(t i n) = 59.5`
`:.` Valence of tin `= (A)/(E) = (118.69)/(59.5) = 2` (an integer)
Thus `Sn^(2+)+2e rarr Sn`
or tin is in `+2` oxidation state.

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