Correct Answer - D
`AgNO_(3) + KCl_((aq.)) rarr AgCl_((s)) + KNO_(3(aq.))`
Initially there is `aq. KCl` solution now as solution of `AgNO_(3)` is added, `AgCl_(s)` is formed. Hence conductivity of solution is almost compensted (or slightly increase) by the formation of `KNO_(3)`. After and point conductivity increases more rapidly because addition of excess `AgNO_(3)` solution.