Question

Find the volume of `Cl_(2)` at `NTP` produced during electrolysis of `MgCl_(2)` which produces `6.6 g Mg`. `("At.wt. of " Mg = 24.3)`

Answer 1

Correct Answer - 6
At cathode `Mg^(2+) + 2e rarr Mg`
At anode `2Cl^(-) rarr Cl_(2) + 2e`
`:.` Equivalent of `Mg` at cathode `=` Equivalent of `Cl_(2)` at anode
`:. (6.6)/(24.3//2) = w_(Cl_(2))/35.5" "implies w_(Cl_(2))=19.28 g`
Now at NTP `PV=w/m RT`
`1xxV=(19.28xx0.0821xx273)/(71)`
`implies " "V=6.08` litre `~~6` litre