Correct Answer - 4
`{:(NitoNi^(+)+2e,,E_(OP)^(@)=0.236 V),(2H^(+)+2etoH_(2),,E_(RP)^(@)=0),(,bar(E_("cell")^(@)=0.236 V)):}`
`E_(cell) = E_(cell)^(@) +(0.059)/(2)"log"_(10)([H^(+)]^(2))/([Ni^(2+)])`
`0 = 0.236 + (0.059)/(2)"log"_(10)[H^(+)]^(2)`
`log_(10)H^(+) = 4 :. pH = 4`