Correct Answer - C
If `theta` critical angle between the pair of media in contact, then from Fig.
`tan theta = (11.54//2)/(10) = (5.77)/(10) = 0.577`
`:. theta = 30^(@)`
Now `.^(1)mu_(2) = (1)/(sin theta) = (2.72)/(mu) = (1)/(sin 30^(@)) = 2`
`2 mu = 2.72, mu = 1.36`