Question

Calculate normality of the mixure obtained by mixing `100ml` of `0.1N HCL` and `50 ml` of `0.25N NaOH` solution
A. ` 0.0467 N `
B. ` 0.0367 N `
C. ` 0.0267N `
D. ` 0.0167N `

Answer 1

Correct Answer - D
Meq.of HCl=`100xx0.1=10`
Meq. of NaOH=`50xx0.25=1.25`
`:.`HCl and NaOH neturalized each other with equal. Eq.
Meq. Of NaOH
left=`12.5-10=2.5`
Volume of new solution =`100+50=150ml.`
`N_(NAOH)`left=`(2.5)/(150)=0.0167N`
Hence normality of the mixture obtained is `0.0167N`