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Determine the binary equivalent of `(6.25)_(10)`.

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Here, `6.25=6+0.25`
We determine separately, the binary equivalent of 6 and 0.25. it is found that
`(6)_(10)=(110)_(2)` and `(0.25)_(10)=(.01)_(2)`
`:. (6.25)_(10)=(110.01)_(2)`

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