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A `PN` junction diode when forward biased has a drop of `0.5 V` which is assumed to be independent of current. The current in excess of `10 mA` through the diode produces large joule heating which damages the diode. If we diode, the resistor used in series with the diode so that the maximum current does not exceed `5 mA` is.
image.

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Correct Answer - B
Let R be the resistance of resistor used in series with p-n junction diode in the circuit. Then
`I=((1.5-0.5))/R=1.0/R`
or `R=1.0/I=(1.0V)/(5 mA)=200Omega=2xx10^(2)Omega`

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