Question

Subtract the second polynomial from the first. 

i. x² – 9x + √3 ; – 19x + √3 + 7x² 

ii. 2ab² + 3a²b – 4ab; 3ab – 8ab² + 2a²b

Answer 1

i. x² – 9x + √3 -(- 19x + √3 + 7x² ) 

= x² – 9x + √3 + 19x – √ 3 – 7x²

= x² – 7x² – 9x + 19x + √3 – √3 

= – 6x² + 10x

ii. (2ab² + 3a²b – 4ab) – (3ab – 8ab² + 2a²b) 

= 2ab² + 3a²b – 4ab – 3ab + 8ab² – 2a²b 

= 2ab² + 8ab² + 3a²b – 2a²b – 4ab – 3ab 

= 10ab² + a²b – 7ab