Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
159 views
in Physics by (98.2k points)
closed by
Two metallic spheres of radii `1 cm` and `2 cm` are given charges `10^(-2) C` and `5 xx 10^(-2) C` respectively. If they are connected by a conducting wire, the final charge on the smaller sphere is
A. `2xx10^(-2) C`
B. `3xx10^(-2) C`
C. `4xx10^(-2) C`
D. `1xx10^(-2) C`

1 Answer

+1 vote
by (97.9k points)
selected by
 
Best answer
Correct Answer - B
Here, `r_(1) = 1 cm, r_(2) = 3 cm`,
`q_(1) = -10^(-2) C, q_(2) = 5xx10^(-2) C`
When the two spheres are connected by a conducting wire, charge flows second sphere to first sphere till their potentials become equal.If bigger sphere loses charge `x xx 10^(-2)`coulomb, then as `V_(1) = V_(2)`
`:. (k (x -1) 10^(-2))/(1 xx 10^(-2)) = (k (5-x) 10^(-2))/(3xx10^(-2))`
`3x - 3 = 5-x, 4x =8, x = 2`
`:.` Charge left on bigger sphere `= (5-2) 10^(-2) C`
`= 3xx10^(-2) C`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...