Question

Find the resistivity of a conductor in which a current density of 2.5 `A m^(-2)` is found to exist, when an electric field of `15 V m^(-1)` is applied on it.

Answer 1

Here, `J=2.5 Am^(-2) ,E=15 Vm^(-1)`
Resistivity, `rho = (RA)/(l) = (V)/(I) (A)/(l) =(V//l)/(I//A) = (E)/(J) = (15)/(2.5)`
`= 6 Omega m`