Question

What volume of water is required to make 0.20 N solution from 1600 mL of 0.2050 N solution?

Answer 1

Meq. of conc. solution = 1600 x 0.2050 = 328

Let after dilution of volume becomes V mL 

Meq. of dil. solution = 0.20 x V 

328 = 0.20 x V

( Meq. does not change on dilution) 

V = 1640 mL

Thus, volume of water used to prepare 1640 mL of 0.20 TV solution 

= 1640- 1600 = 40 mL