Question

A given `AM` transmitter develops an unmodulated power out put of `1 KW` across `50 Omega` resistance. When a message signal of amplitude `5 V` is applied on it then the side bands carry `40%` of power of carrier. Amplitude of the carrier signal used is
A. `505.952 V`
B. `126.488`
C. `252.976`
D. `316.22`

Answer 1

Correct Answer - D
`P_(c)=(A_(C)^(2))/(2R)=1kWimplies(A_(c)^(2))/(2xx50)=10^(3)`