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ABDC is a quadrant of a circle of radius 28 cm and a semi-circle BEC is drawn with BC as diameter.

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ABDC is a quadrant of a circle of radius 28 cm and a semi-circle BEC is drawn with BC as diameter. Find the area of the shaded region. ( Use π = 22 / 7)

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Area of the shaded region = Area of semi - circle + area of Δ - Area of quadrant

= 616 + 392 - 616

= 392 cm2.

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