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Given A ≡ (1, 1) and AB is any line through it cutting the x-axis in B. If AC is perpendicular to AB and meets the y-axis in C,

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Given A ≡ (1, 1) and AB is any line through it cutting the x-axis in B. If AC is perpendicular to AB and meets the y-axis in C, then the equation of locus of mid- point P of BC is 

(A) x + y = 1 

(B) x + y = 2 

(C) x + y = 2xy 

(D) 2x + 2y = 1

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(A) x + y = 1 

y – 1 = m (x – 1)

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