Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
50 views
in Chemistry by (88.6k points)
closed by
The coagulation of `100mL` of a colloidal solution of gold is completely prevented by adding `0.25g` of starch to it before adding `10mL` of `10%NaCl` solution. The gold number of starch is
A. `25`
B. `2.5`
C. `250`
D. `0.25`

1 Answer

0 votes
by (90.5k points)
selected by
 
Best answer
Correct Answer - A
To calculate gold number, we must take `10mL` of gold sol and add `1mL` of a `10%` solution of `NaCl` to it. Finally we must express the answer in milligrams.
Here `10mL` of `10%NaCl` is added to `100mL` of gold sol. Thus, `1mL` of `10%NaCl` solution is added to `10mL` of gold sol. `100mL` of `10%NaCl` solution is added to `10mL` of gold sol. `100mL` gold sol requires `0.25g` starch or `0.25xx10^(3)mg` starch. Thus, `10mL` gold sols will require.
`(0.25xx10^(3))/(100)xx10mg=25mg`
Thus, by definition, the gold number of starch is `25` .

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...