Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
319 views
in Physics by (87.2k points)
closed by
Charge `q_(1)` is fixed and another point charge `q_(2)` is placed at a distance `r_(0)` form `q_(1)` on a frictionless horizontal surface.Find the velocity of `q_(2)` as a function of seperation `r` between them (treat the changes as point charges and mass of `q_(2)` is m)

1 Answer

0 votes
by (84.7k points)
selected by
 
Best answer
image
Accoding law of concervation energy
`U_(1)+K_(1)=U(2)+K_(2)`
` (1)/(4piepsilon_(0))(q_(1)q_(2))/(r_(0))+0=(1)/(4piepsilon_(0))=(1)/(4piepsilon_(0))(q_(1)q_(2))/(r)+(1)/(2)mv^(2)`
`(1)/(2)mv^(2)=(q_(1)q_(2))/(4piepsilon_(0))[(1)/(r_(0))-(1)/(r)],v=sqrt((q_(1)q_(2))/(2piepsilon_(0)m))[(1)/r_(0)-(1)/(r)]`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...