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The maximum wavelength of Brackett series of hydrogen atom will be _____`A^(@)`
A. `35,890`
B. `14,440`
C. `62,160`
D. `40,477`

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Correct Answer - D
`RZ^(2)(1/n_(1)^(2)-1/n^(2_(2)))=1/lambda "where" n_(1)=4:n_(2)=5`

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