Question

Calculate the energy released by fission from `2 g` of `.^(235)._(92)U` in `kWh`. Given that the energy released per fission is `200 MeV`.

Answer 1

Mass of uranium `= 2g`
Energy released per fission `= 200 MeV`
`=200xx10^(6)xx1.6xx10^(-19)=3.2xx10^(-11)J`
Number of atoms in `2` gram of uranium is
`n=(2xx6.023xx10^(23))/(235)=5.125xx10^(21)"atoms"`
Total energy released `=`No. of atoms `x` energy released per fission
`=5.125xx10^(21)xx3.2xx10^(-11)=16.4xx10^(10)J`
`=0.455xx10^(5)Kwh=4.55xx10^(4)Kwh`