Question

The minimum energy required for the emission of photo electron from the surface of a metal is 4.95 x 10^-19 J. Calculate the critical frequency and the corresponding wavelength of the photon required to eject the electron, h = 6.6 x 10^-34 J sec.

Answer 1

Minimum energy required for the emission of photo electrons = 4.95 x 10^-19 J

Let the critical frequency or threshold frequency of the photon to eject the electron be v sec^-1

We know, E = hv or v = E/h