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The value of `mu^(prop)` for `NH_(4)CI, NaOH` and `NaCI` are `129.8, 248.1` and `126.4 ohm^(-1) cm^(2) mol^(-1)` respectively. Calculate `mu^(prop)` f

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The value of `mu^(prop)` for `NH_(4)CI, NaOH` and `NaCI` are `129.8, 248.1` and `126.4 ohm^(-1) cm^(2) mol^(-1)` respectively. Calculate `mu^(prop)` for `NH_(3)OH` solution.
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`mu_(NH_(4)OH)^(prop) = mu_(NH_(4)CI)^(prop) +mu_(NaOH)^(prop) - mu_(NaCI)^(prop)`
`= 129.8 +248.1 - 126.4`
`mu_(NH_(4)OH)^(prop) = 251.5 ohm^(-1) cm^(2) mol^(-1)`
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