Question

At `25^(@)C, {:(Ag+I^(-)rarr,AgI+e,,E^(@) =0.152V),(Agrarr,Ag.^(+)+e,,E^(@) =- 0.80V):}`
The `log K_(sp)` of `AgI` is: `((2.303RT)/(F)=0.059)`
A. `-8.12`
B. `+8.612`
C. `-37.83`
D. `-16.13`

Answer 1

Correct Answer - D
`Ag^(+) +e rarr Ag, E_(R)^(@) = 0.8`
`Ag + I^(-) rarr AgI +e, E_(R)^(@) =- 0.152`
`Ag^(+) +I^(-) rarr AgI, E_(cell)^(@) = 0.952`
`E^(@) = 0.059 log.(1)/(K_(sp))`
`0.952 =- 0.059 log K_(sp)`
`:. Log K_(sp) = (-952)/(0.059) = -16.13`