Question

When two identical bar magnets placed one above the other, such that they are mutually perpendicular and bisect each other. The time period oscillation in a horizontal magnetic field is `4` seconds. If one of the magnets is removed the time period of the other in the same field `(2^(1//4)=1.189)`
A. `1.34sec`
B. `2.34sec`
C. `3.36sec`
D. `4.34sec`

Answer 1

Correct Answer - C
`T=2pisqrt((I)/(MB_(H))`
and `(T_(1))/(T_(2))=sqrt((I_(1))/(I_(2))xx(M_(2))/(M_(1)))=sqrt((2I)/(I)xx(M)/(sqrt2M))=2^(1//4)`