Correct Answer - A
Consider the differential element of the cylinder as shown in the figure.
`thereforeR=underset(R_(1))overset(R_(2))intrho(dx)/(2pixl)" "(becauseR=rho(l)/(a))`
`impliesR=(rho)/(2pil)"In"(R_(2)//R_(1))`
`I=(epsilon)/(R),impliesI=(2pi//epsilon)/(rho"In"((R_(2))/(R_(1))))`