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If `3A rarr 2B`, then the rate of reaction of `+ (dB)/(d t)` is equal to
A. `- (3)/(2) (d[A])/(dt)`
B. `- (2)/(3) (d[A])/(dt)`
C. `- (1)/(3) (d[A])/(dt)`
D. `+ 2(d[A])/(dt)`

1 Answer

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Best answer
Correct Answer - B
For the reaction
`3Ararr2B`
`Rate `=-(d[A])/(3dt)=+(d[B])/(2dt)`
Thus, `+(d[B])/(dt)=-(2)/(3)=-(2)/(3)(d[A])/(dt)`

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