Question

A particle moves in `x-y` plane according to the law `x = 4 sin 6t and y = 4 (1-cos 6t)`. The distance traversed by the particle in 4 second is (`x & y` are in meters)
A. `96m`
B. `45m`
C. `24m`
D. `108m`

Answer 1

Correct Answer - A
A particle ……………
Distance `= sqrt((dx)^(2)+(dy)^(2))`
`= sqrt(((dx)/(dt))^(2)+((dy)/(dt))^(2))dt`
`= sqrt((24sin6t)^(2)+(24cos6t)^(2))dt = 24int_(0)^(4)dt = 96 m`