With usual notations prove that 2{a sin^2 C/2 + c sin^2 A/2} = a – b + c.

Question

With usual notations prove that 

2{a sin² + \(\cfrac{C}{2}\) +  c sin² + \(\cfrac{A}{2}\)} = a – b + c.

2{a sin² C/2 + csin² A/2} = a – b + c.

Answer 1

2{a sin² + \(\cfrac{C}{2}\) +  c sin² + \(\cfrac{A}{2}\)} = a – b + c.