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A block is attached with an ideal spring and string, and is in equilibrkum as shown in Figure. The acceleration of the block just after breaking the string is `a_(1)` and just after breaking the spring is `a_(2)`. Then
image
A. `a_(1) = (5g)/(8)`
B. `a_(2) - (3g)/(5)`
C. `a_(1) = (g)/(2)`
D. `a_(2)=g`

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Best answer
Correct Answer - A::B
`Kx sin 53^(@) + T sin 53^(@) =mg`
`Kx=T 2Kx (4)/(5)mg Kx =(5)/(8)mg`
image
If string break `a_(1) = (5 mg//8)/(m) = 5g//8`
If spring break, `a_(2)=g cos 53^(@)=3 g//5`

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