Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
8.7k views
in Chemistry by (88.1k points)
closed by
The resistance of `0.1N` solution of formic acid is `200 ohm` and cell constant is `2.0 cm^(-1)`. The equivalent conductivity ( in `Scm^(2) eq^(-1))` of `0.1N` formic acid is `:`
A. 100
B. 10
C. 1
D. none of these

1 Answer

0 votes
by (89.4k points)
selected by
 
Best answer
Correct Answer - 1
`k=G.G^(@)" "rArr" "(1)/(200)xx2" "=0.01,`
`Lambda_(eq)=(k)/(N)xx1000" "rArr" "(0.01)/(0.1)xx1000rArr100`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...