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If ω( ≠ 1) is a cubic root of unity, then Δ = |(1 1+i+ω^2 ω^2), (1-i -1 ω^2-1), (-i -1+ω-i -1)| is equal to

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If ω( ≠ 1) is a cubic root of unity, then Δ = |(1  1+i+ω2  ω2), (1-i  -1  ω2-1), (-i  -1+ω-i  -1)| is equal to

(a) 0

(b) 1

(c) i

(d) ω

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Correct option (a) 0

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