Question

Find the principal solutions of the following equations :

tan3θ = -1

Answer 1

Since, θ ∈ (0, 2π), 3∈ ∈ (0, 6π)

… [∵ tan(π – θ) = tan(2π – θ) = tan(3π – θ) 

= tan (4π – θ) = tan (5π – θ) = tan (6π – θ) = - tan θ]